A donkey pulls a cart(c) with a mass of 240kg, attached to a log of wood(w), with a mass of 80kg on a horizontal road. W is tied to the back of c by means of non elastic rope. The donkey applies a foce of 170N on Cart c and the system accelerates at 0,3m s-2 to the left. The force of friction on the cart in 40N. The rope has negligible mass.
How do I draw a diagram for cart c, indicating and labelling all the forces acting on it and how do I calculate the magnitude of the force which the rope exerts on c and the force of friction on w?
The magnitude of the force on w is...
170 - friction - masscart*acceleration.
There is a flaw in this problem: the non elastic rope pulling w...technically, non elastic means it can be absorbing energy, meaning the force at the front of w may not be the same force at the back at w. I suppose your teacher did not mean this...
you are stupied
How can i calculate magnitude of the force and also the force of friction on w
A donkey 1 pulls a chart to the left. Then donkey 2 is also tied to the chart and pulls to the left with same force. Draw a vector diagrams showing the force the two donkey exert and rusltant force
Help am confused
To draw a diagram for cart C and label the forces acting on it, you can follow these steps:
1. Draw a rectangle to represent the cart C.
2. Label the mass of the cart as "240 kg" near the rectangle.
3. Draw an arrow pointing to the left to represent the force applied by the donkey, which is 170N. Label it as "Force applied by donkey".
4. Draw an arrow pointing to the right, opposite to the force applied by the donkey, to represent the force of friction. Label it as "Force of friction".
5. Draw an arrow pointing to the left to represent the force exerted by the rope on the cart C. Label it as "Force exerted by rope on cart C".
To calculate the magnitude of the force exerted by the rope on cart C, you need to consider the forces acting on the system. The net force acting on the system is equal to the mass of cart C multiplied by its acceleration. In this case, the net force is 240 kg * 0.3 m/s^2 = 72 N.
Since the force of friction on the cart C is given as 40 N, you can calculate the magnitude of the force exerted by the rope on cart C by subtracting the force of friction from the net force:
Magnitude of force exerted by rope on cart C = Net force - Force of friction
= 72 N - 40 N
= 32 N.
Thus, the magnitude of the force exerted by the rope on cart C is 32 N.
The force of friction on the log of wood W can be calculated using the equation you mentioned:
Force of friction on W = Force applied by the donkey - Force exerted by the rope on cart C - Mass of cart C * acceleration
Force of friction on W = 170 N - 32 N - 240 kg * 0.3 m/s^2
= 170 N - 32 N - 72 N
= 106 N.
Therefore, the force of friction on the log of wood W is 106 N.