Math

Expand (3+i)^5, where i^2=-1

(3+i)^5=?

Please and thanks.

asked by Philip
  1. shifting to polar..
    3+i= sqrt10 @arctan(1/3) on the complex plane
    so
    (3+i)^5=(sqrt10)^2 @5*arctan(1/3)
    and that is
    100sqrt10 @5*18.4349488deg
    100sqrt10 @92.17 deg
    converting back to complex plane
    real+ imag where
    real=100Sqrt10*cos91.17
    imag=i*100sqrt10*sin91.17

    posted by bobpursley

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