A military jet is flying at 224 m/s in a tight circular turn. If the military jet reaches a centripetal acceleration of 8.00 times the free-fall acceleration, what must the radius of its turn be?

Thanks!

To find the radius of the turn, we can use the following formula:

Centripetal acceleration (ac) = (v^2) / r

Where:
- ac is the centripetal acceleration
- v is the velocity of the jet
- r is the radius of the turn

We are given that the centripetal acceleration is 8.00 times the free-fall acceleration (g). Thus, ac = 8g.

First, let's calculate the value of free-fall acceleration (g):
- On Earth, the approximate value of the acceleration due to gravity is 9.8 m/s^2.

Now we can substitute the given values into the formula and solve for r:

8g = (224^2) / r

Since we know the value of g, let's substitute it in:

8 * 9.8 = (224^2) / r

Simplifying:

78.4 = (224^2) / r

To isolate r, we can rearrange the equation:

r = (224^2) / 78.4

Calculating this expression will give us the radius of the jet's turn.

9.8=224^2/r

r=you do it.