A military jet is flying at 224 m/s in a tight circular turn. If the military jet reaches a centripetal acceleration of 8.00 times the free-fall acceleration, what must the radius of its turn be?
Thanks!
To find the radius of the turn, we can use the following formula:
Centripetal acceleration (ac) = (v^2) / r
Where:
- ac is the centripetal acceleration
- v is the velocity of the jet
- r is the radius of the turn
We are given that the centripetal acceleration is 8.00 times the free-fall acceleration (g). Thus, ac = 8g.
First, let's calculate the value of free-fall acceleration (g):
- On Earth, the approximate value of the acceleration due to gravity is 9.8 m/s^2.
Now we can substitute the given values into the formula and solve for r:
8g = (224^2) / r
Since we know the value of g, let's substitute it in:
8 * 9.8 = (224^2) / r
Simplifying:
78.4 = (224^2) / r
To isolate r, we can rearrange the equation:
r = (224^2) / 78.4
Calculating this expression will give us the radius of the jet's turn.
9.8=224^2/r
r=you do it.