what are the mean,median,mode, and range of the data set given the altitude of lakes in feet:-11,-28,-17,-25,-28,-39,-6,and -46?
A. mean= -25; median= -26.5; mode= -28; range=40
B. mean= -25; median=-40; mode=-26.5; range=28
C. mean= -26.5; median= -25; mode= -28; range=28***
D. mean=-26.5; median=-28; mode=-25; range=40
given the data 12,39,21,18,24,17,12,25.
a. what is the outlier in the data?
b. what is the mean with the outlier?
c. what is the mean without the outlier?
A. 12;21;18.4
B. 12;18.4;21
C. 39;21;18.4**
D. 39;18.4;21
so i'm guessing this won't work for tx connections academy lmao.
-Ya'llMakeMeFacePalm._.
I have 20 questions can someone plz tell answers rn 🥹 luv y’all bye 🫶🏼Have a very nice day or night ✌🏻
i only have 19 questions and question 19 is the only essay question so anyone have the multiple choice questions for that???
Same I Have 20 questions and its due today 3/15/23
ok people this are the answers
1.A
2.B
3.B
4.B
5.C
6.C
7.B
8.B
9.D
10.A
11.D
12.B
13.C
14.A
15.D
16.C
17.B
TRUST ME I AM SO SAD THAT I DID NOT GOT THE ANSWERS RIGTH BUT, ILL BE NICE AND GIVE YOU the answers
uwu
Do you know how to get mean, median, mode, and range?
Mean: Add up all the data and divide by the original total of numbers
Median: Set up the numbers in order from least to greatest, the number in the middle is the median.
Mode: The number that shows up the most. Ex: 1123 the mode is 1
Range: Subtract the lowest number by the highest number. Ex: 3,4,5,6,9.......9-3=6
I got 5/17 thx appreciate it
I got 5/17 thx appreciate it and I’m in Cali
PLEASE LISTEN to me people, Do not do listen to the answer in the top, because it not correct, PLEASE FOR YOURE GOOD PLEASE LISTEN TO ME.
Thanks alot lopalog you failed me, I got 2/17
Got a 5/17
What are the mean, median, mode, and range of the data set given the altitude of lakes in feet:
–11, –28, –17, –25, –28, –39, –6, and –46?
A. mean = –25; median = –26.5; mode = –28; range = 40
B. mean = –25; median = –40; mode = –26.5; range = 28
C. mean = –26.5; median = –25; mode = –28; range = 28
D. mean = –26.5; median = –28; mode = –25; range = 40
The correct answer is C.
Mean: (-11) + (-28) + (-17) + (-25) + (-28) + (-39) + (-6) + (-46) = -225 / 8 = -28.125
Median: Put the data set in order from least to greatest: -46, -39, -28, -28, -25, -17, -11, -6. The median is the number in the middle, which is -25.
Mode: The mode is the number that appears most frequently. In this case, -28 is the mode because it appears twice.
Range: The range is the difference between the largest and smallest numbers. The smallest is -46 and the largest is -6, so the range is 40.
given the data 12,39,21,18,24,17,12,25.
a. what is the outlier in the data?
b. what is the mean with the outlier?
c. what is the mean without the outlier?
a. The outlier is 39 because the outlier the the number that is significantly larger or smaller than the rest of the data.
b. What is the mean with the outlier
1) 12 + 39 + 21 + 18 + 24 + 17 + 12 + 25 = 168
2) Divide 168 by 8 , since there are 8 numbers in the data
168 / 8 = 21
c. What is the mean without the outlier
1) 168 - 39 (outlier) = 129
2) Divide 129 by 7, since there are 7 number, remember you took out the outlier.
129 / 7 = 18.4
So yes, your answer was correct. Great job!!!!
Hello Zeeko, you needed to make sure that we attend the same school. This was for California Connections Academy. This is school is in over half of the states. That's too bad you got an 8/17, But I bet you can ask your teacher to reset your test to give you another chance. Good luck to you.
Yup this is for the california exam. Completed it just now and got 100% on the multiple choice waiting for my teacher to grade the workpad problems
one hundred percent yeah I am in cali
For Texas:
1. D
2. D
3. B
4. C
5. A
6. C
7. D
8. C
9. A
10. A
11. C
12. B
13. A
14. D
15. A
16. D
17. A
18. D
19. Do it yourself
Is there anything else I can assist you with?
Yeah I know how to find the mean, median, mode, and range. I used these *** so someone could check my answer.
17/17 katey perry's california lol
I'm sorry to hear that, but unfortunately, cheating is not the right way to succeed. It's important to take responsibility for our own learning and to strive for genuine understanding rather than just looking for quick answers. Continuous hard work and effort are the keys to success.
What are the mean, median, mode and range of the data set given the altitude of lakes in feet: –11, –28, –17, –25, –28, –39, –6, and –46?
Mean: Add all the data
-11 + (- 28 ) + (- 17) + (- 25) + (- 25 ) + ( -28) + (-39) + (- 6) + (- 46 ) = - 225
Divide - 225 by 9
- 225 / 9 = 25
***25 is the mean
Median: Put the data in order from least to greatest
- 46, - 39, -28, -28, -25, -17, -11, -6
Add the two numbers in the middle: -28 + ( -25) = - 43
Divide -43 by 2: -43 / 2 = - 21.5
*** 21.5 is the median
Mode: -28 , it occurs the most
**28 is the range
Range: Subtract -46 and -6
- 46 - ( -6) = - 40
*** -40 is the range
For Colorado Academy...
1-A
2-D
3-A
4-C
5-C
6-B
7-B
8-C
9-C
10-A
11- A
12-D
13-C
14-D
15-B
16-D
17-B
18-
0 / . 5
1 / . 2 , . 3 , .3 , . 5
2 / . 2 , . 2 , . 2
3 / 0 , 0
4 / .5
19-
26 students take exactly two classes.
20-
9| 3
6| 9
9| 5
8| 8
9| 4
6| 4
9| 2
8| 8
1| 00
9| 1
9| 7
Please rewrite the essays.
1) C
2) C
3) B
4) C
5) B
6) C
7) A
8) C
9) A
10) A
11) C
12) D
13) B
14) D
15) C
16) D
17) B
18) You can make a stem-and-leaf plot as frequency table for "The chart below shows the average number of movies seen per person in selected countries. "
0 / . 5
1 / . 2 , . 3 , .3 , . 5
2 / . 2 , . 2 , . 2
3 / 0 , 0
4 / .5
19.) Mr. Green teaches band, choir, and math. This year, he has 57 students that take at least one of his classes. He teaches band to 25 students. There are 9 students who have Mr. Green for math and nothing else. Use the Venn diagram below: How many students take exactly 2 classes with Mr. Green?
Answer: 26 students take exactly 2 classes check the work below.
25 - ( 7 + 3 + 11) Use order of operations or pemdas
25 - ( 21 ) = 4 ** students who take both Band and Choir
Add 11 + 7 + 3 + 4 + 17 + 9 = 51
Subtract 57 - 42 = 15***Students take Math and Choir
Add 15 + 4 + 7 , these are the sections in the Venn Diagram where two circles share the same space.
15 + 4 + 7 = 26 ***** ANSWER
26 students take exactly two classes.
20.) Another stem-and-leaf plot problem.
| Percentage of
Countries | Households with Color Television
9| 3
6| 9
9| 5
8| 8
9| 4
6| 4
9| 2
8| 8
1| 00
9| 1
9| 7