What is the force constant of a spring which is stretched 2mm by a force of 4N
what is 4N/.002m ?
To find the force constant of a spring, we can use Hooke's Law, which states that the force applied to a spring is directly proportional to the displacement of the spring from its equilibrium position.
Hooke's Law is expressed as:
F = -kx
Where:
F is the force applied to the spring,
k is the force constant (also known as the spring constant),
x is the displacement of the spring from its equilibrium position.
Given the force applied (F) is 4N and the displacement (x) is 2mm (0.002m), we can rearrange the equation to solve for the force constant (k).
k = -F / x
Substituting the given values:
k = -4N / 0.002m
Simplifying the expression:
k = -2000 N/m
Therefore, the force constant of the spring is -2000 N/m. Note that the negative sign indicates that the force exerted by the spring opposes the direction of displacement.