1.Name the type of solution 45g of NaCl in 100g of water at 80 degree celcius.
2. 39g of NaCl in 100g of water at 80 degree celcius
You need to look up the solubility of NaCl in water at 80 C, then assign saturated, unsaturated, supersaturated
Unsaturated
To determine the type of solution, we need to compare the amount of solute (NaCl) with the solvent (water).
1. In the first case, we have 45g of NaCl dissolved in 100g of water at 80 degrees Celsius.
The first step is to calculate the concentration of the solution, which is given by the formula:
Concentration (g/mL) = Mass of Solute (g) / Volume of Solution (mL)
Since we are dealing with a liquid solution, we assume that the volume of the solution is equal to the volume of the solvent. So, in this case, the concentration is:
Concentration = 45g / 100g = 0.45 g/mL
Next, we need to determine if the solution is saturated, unsaturated, or supersaturated.
- If the concentration is less than the solubility at that temperature, the solution is unsaturated.
- If the concentration is equal to the solubility, the solution is saturated.
- If the concentration is greater than the solubility, the solution is supersaturated.
To determine the solubility of NaCl in water at 80 degrees Celsius, you would need to refer to a solubility table or chart. The solubility can vary depending on factors such as temperature.
2. Similarly, for the second case with 39g of NaCl dissolved in 100g of water at 80 degrees Celsius, you would follow the same steps to calculate the concentration and determine the type of solution.