A chemist mixed some 20% peroxide sol with some 30% peroxide sol to make 500ml of a 25% peroxide solution.How many ml of each solution should be used? HELP just cannot get this one..
wouldn't you have something like
.20(x) + .30(500-x) = .25(500) ?
Thanks, will try working that again.
To solve this problem, we can set up an equation based on the given information. Let's call the amount of 20% peroxide solution used as x (in ml) and the amount of 30% peroxide solution used as (500-x) (in ml).
We know that the total amount of the solution is 500 ml, so we have the equation:
x + (500 - x) = 500
Now let's calculate the amount of pure peroxide in each solution.
For the 20% peroxide solution, 20% of x ml is pure peroxide. Therefore, we have:
0.20x ml of pure peroxide from the 20% solution
For the 30% peroxide solution, 30% of (500 - x) ml is pure peroxide. Therefore, we have:
0.30(500 - x) ml of pure peroxide from the 30% solution
According to the problem, the resulting mixture is a 25% peroxide solution. Therefore, we can set up another equation based on the amount of pure peroxide in the mixture:
0.20x + 0.30(500 - x) = 0.25(500)
Now we can solve this equation to find the values of x and (500 - x). The steps are as follows:
0.20x + 0.30(500 - x) = 0.25(500)
0.20x + 150 - 0.30x = 125
0.10x = 125 - 150
0.10x = -25
Divide both sides of the equation by 0.10:
x = -25 / 0.10
x = -250 ml
Since we can't have a negative amount of solution, there must be an error in the calculation. Please review the given information and check for any mistakes in the numbers provided.