the area of four walls of a room is 480m. if the length of the room is twice its breadth and the height 8m find the areaof the floor.
Width = W meters.
Length = 2W meters.
W * 2W = 480 m^2.
2W^2 - 480 = 0, W^2 - 240 = W = 15.5 Meters.
2W = 2 * 15.5 = 31 Meters.
To find the area of the floor, we first need to determine the dimensions of the room. Let's break down the problem step by step:
1. Let's assume the length of the room is "L", and the breadth is "B". We are given that the height of the room is 8m.
2. The area of four walls of the room can be calculated by adding the areas of all four walls. Since we know the height is 8m, the formula for the area of the four walls would be 2(L + B) * 8, which simplifies to 16(L + B).
3. We are given that the area of the four walls is 480m. So we can write the equation as 16(L + B) = 480.
4. Now, let's use the information provided in the problem statement to relate the length and breadth of the room. The problem states that the length of the room is twice its breadth, which can be written as L = 2B.
5. Substitute L = 2B into the equation 16(L + B) = 480. We get 16(2B + B) = 480.
6. Simplifying, we have 16(3B) = 480, which further simplifies to 48B = 480.
7. Divide both sides of the equation by 48: B = 10.
8. Substitute the value of B into L = 2B: L = 2 * 10 = 20.
9. Now that we have determined the length (L = 20) and breadth (B = 10) of the room, we can calculate the area of the floor by multiplying L and B: Area of floor = L * B = 20 * 10 = 200 square meters.
Therefore, the area of the floor is 200 square meters.