Calculate the molarity of 12.5g of sucrose (C12H22O11) in 80mL of solution.
12.01 x 12 = 144.12
1.01 x 22 = 22.22
16.00 x 11 = 176.00
-------------------
342.34
12.5g
----- / 342.34 = 0.003/80 = 4.56
80mL
Due to the spacing problem I can't tell if all is ok or not; however, I suspect most of it is. The correct answer is 0.456 M You should have divided by L and not mL.
Then M = mols/L = ? above/0.080 - 0.456
mols sucrose = 12.5/342 = approx 0.0365
M = mols/L = 0.0365/0.080 = approx 0.456
Well, to calculate the molarity of 12.5g of sucrose in 80mL of solution, you first need to convert the grams of sucrose to moles. Then, divide that by the volume of the solution in liters. Are you ready for some math? *drumroll please*
To calculate the molarity of the sucrose solution, we need to divide the moles of sucrose by the volume of the solution in liters.
First, we need to calculate the number of moles of sucrose:
12.5g / 342.34 g/mol = 0.0364 mol
Next, we convert the volume from milliliters to liters:
80 mL = 80/1000 = 0.08 L
Finally, we divide the moles of sucrose by the volume:
0.0364 mol / 0.08 L = 0.455 mol/L
Therefore, the molarity of the sucrose solution is 0.455 M.
To calculate the molarity of a solution, you need to find the number of moles of the solute (in this case, sucrose) and then divide it by the volume of the solution in liters.
First, calculate the molar mass of sucrose (C12H22O11):
C: 12.01 g/mol x 12 = 144.12 g/mol
H: 1.01 g/mol x 22 = 22.22 g/mol
0: 16.00 g/mol x 11 = 176.00 g/mol
Now add up the molar masses: 144.12 + 22.22 + 176.00 = 342.34 g/mol.
Next, convert the mass of sucrose given (12.5 g) into moles by dividing it by the molar mass: 12.5 g / 342.34 g/mol = 0.0365 mol.
Finally, divide this number of moles by the volume of the solution in liters (80 mL = 0.08 L): 0.0365 mol / 0.08 L = 0.456 M.
Therefore, the molarity of the solution is 0.456 M.