Select the points that lie on the function H(x)=3x^2
(1,3)
(1,9)
(-1,-3)
or
(-1,3)
square the x value and multiply by 3.. if that value equals H(x) or y.
3(1)^2 = 3 this one works.
3(1)^2 = 3 not 9 so the second point doesn't lie on the function.
Your try the last 2
(1,3) AND (1,9)
To determine which points lie on the function H(x) = 3x^2, we substitute the x-values into the function and check if the y-values match.
Let's evaluate the points:
(1, 3):
Plugging in x = 1, we get H(1) = 3(1)^2 = 3(1) = 3. So, the point (1, 3) lies on the function H(x) = 3x^2.
(1, 9):
Plugging in x = 1, we get H(1) = 3(1)^2 = 3(1) = 3. However, the given point is (1, 9), and the y-value is not equal to 3. So, the point (1, 9) does not lie on the function H(x) = 3x^2.
(-1, -3):
Plugging in x = -1, we get H(-1) = 3(-1)^2 = 3(1) = 3. However, the given point is (-1, -3), and the y-value is not equal to 3. So, the point (-1, -3) does not lie on the function H(x) = 3x^2.
(-1, 3):
Plugging in x = -1, we get H(-1) = 3(-1)^2 = 3(1) = 3. So, the point (-1, 3) lies on the function H(x) = 3x^2.
Therefore, the points that lie on the function H(x) = 3x^2 are (1, 3) and (-1, 3).
To determine which points lie on the function H(x) = 3x^2, we need to substitute the given x values into the function and check if the resulting y values match the given y values.
Let's go through each point:
Point (1,3):
Substituting x = 1 into the function H(x) = 3x^2:
H(1) = 3(1)^2 = 3(1) = 3
The y-value obtained is 3, which matches the given y-value of 3. So, the point (1,3) lies on the function H(x) = 3x^2.
Point (1,9):
Substituting x = 1 into the function H(x) = 3x^2:
H(1) = 3(1)^2 = 3(1) = 3
The y-value obtained is 3, which does not match the given y-value of 9. So, the point (1,9) does not lie on the function H(x) = 3x^2.
Point (-1,-3):
Substituting x = -1 into the function H(x) = 3x^2:
H(-1) = 3(-1)^2 = 3(1) = 3
The y-value obtained is 3, which does not match the given y-value of -3. So, the point (-1,-3) does not lie on the function H(x) = 3x^2.
Point (-1,3):
Substituting x = -1 into the function H(x) = 3x^2:
H(-1) = 3(-1)^2 = 3(1) = 3
The y-value obtained is 3, which matches the given y-value of 3. So, the point (-1,3) lies on the function H(x) = 3x^2.
Therefore, the points that lie on the function H(x) = 3x^2 are (1,3) and (-1,3).