a particle is projected horizontally at 15m/s from a height of 20m calculate the horizontal distance covered by the particle just before hitting the ground (g=10m/s square)
how long does it take to hit the ground?
10t^2 = 20
use that t to find the horizontal distance: d = 15t.
rats: 5t^2=20
To calculate the horizontal distance covered by the particle before hitting the ground, you need to use the equations of motion.
The horizontal motion of the particle is unaffected by gravity because it is projected horizontally. Therefore, the initial horizontal velocity (u) remains constant throughout the motion.
Given:
Initial horizontal velocity (u) = 15 m/s
Height of projection (h) = 20 m
Acceleration due to gravity (g) = 10 m/s^2
Since the motion is only in the horizontal direction, we can calculate the time (t) it takes for the particle to hit the ground using the formula:
t = ā(2h / g)
Plugging in the values:
t = ā(2 * 20 / 10) = ā4 = 2 s
Now that we have the time it takes for the particle to hit the ground, we can calculate the horizontal distance (d) covered using the formula:
d = u * t
Plugging in the values:
d = (15 m/s) * (2 s) = 30 m
Therefore, the horizontal distance covered by the particle just before hitting the ground is 30 meters.