A bag contain marbles of three different colours red blue and yellow 2/5of the marbles are red the ratio of three number of blue marbles to the number of yellow marbles is5:7 what fraction of the marbles in the bag is blue
Let's say there are m marbles.
The clues given are:
b+r+y = m
r/m = 2/5
b/y = 5/7
r = 2m/5
y = 7b/5
so
b+r+y = m
b+(2m/5)+(7b/5) = m
12b/5 = 3m/5
b/m = (3/5)(5/12) = 1/4
m marbles in bag
2m/5 are red
so
3 m/5 = b+y
m = r + b + y
b/y = 5/7
or y = 7b/5
3 m/5 = b + 7b/5
3 m/5 = 12 b/5
4 b = m
b = (1/4) m
To find the fraction of the marbles in the bag that are blue, we first need to find the total number of marbles in the bag.
Given that 2/5 of the marbles are red, we can assume that 2 out of every 5 marbles are red.
Let's say the total number of marbles in the bag is "x". Therefore, the number of red marbles is 2/5 * x.
Now, let's focus on the ratio of blue to yellow marbles. The ratio is given as 5:7. This means that for every 5 blue marbles, there are 7 yellow marbles.
Let's say the number of blue marbles is "b" and the number of yellow marbles is "y". Therefore, we have the equation:
5b = 7y
To simplify this equation further, we can divide both sides by 5:
b = (7/5) * y
Now, we need to find the fraction of blue marbles out of the total marbles. To do this, we divide the number of blue marbles by the total number of marbles:
Fraction of blue marbles = b / x
Substituting the value of b, we have:
Fraction of blue marbles = (7/5) * y / x
Since we don't know the values of y and x, we cannot determine the exact fraction of blue marbles without more information.