Physics

A 145-kg object and a 445-kg object are separated by 3.90 m.
(a) Find the magnitude of the net gravitational force exerted by these objects on a 34.0-kg object placed midway between them. (N)

(b) At what position (other than an infinitely remote one) can the 34.0-kg object be placed so as to experience a net force of zero from the other two objects?
(m from the 445 kg mass toward the 145 kg mass)

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  1. a) net force=G34(445 -145 )/d^2 where d is half the separation distance.

    b. let x be the distance from the larger object.
    Then the force is zero at that point. 0=G*34(445/x^2-145/(3.9-x)^2

    or 445/x^2=145/(3.9-x)^2
    (3.9-x)^2=.326 x^2
    take sqrt of both sides
    (3.9-x)=.571 x
    1.571x=3.9
    x=2.48m from the larger object

    check all that math.

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    bobpursley

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