A glacier advances at 7 × 10−6
cm/s. How far will it move in 3.7 y?
Answer in units of cm. I have calculated that there are 31,449,600 seconds in a year. I multiplied 31,449,600 by 7 × 10−6 and got 2201.472. Then I multiplied that by 3.7 and got 8145.4464. I submitted that answer but it was wrong. Can someone help me?
d=v*time
= 7E-6 cm/s *3.7yr*365days/yr*23hrs/day*3600sec/hr*
Put this in your google search window:
7E-6 * 3.7 *365 *23 *3600 =
I get almost eight meters in that time
To calculate how far the glacier will move in 3.7 years, we need to multiply its speed by the time. Let me guide you through the process again with corrected calculations:
First, let's convert the speed from cm/s to cm/year. Since there are 31,449,600 seconds in a year, we can convert the speed to cm/year by multiplying it by the number of seconds in a year:
7 × 10^-6 cm/s * 31,449,600 s/year = 220.14624 cm/year (rounded to 5 decimal places)
Now that we have the speed in cm/year, we can multiply it by the time of 3.7 years to find the distance the glacier will move:
220.14624 cm/year * 3.7 years = 814.771088 cm (rounded to 3 decimal places)
So, the glacier will move approximately 814.771 cm in 3.7 years.