maths asap need help

let the perpendicular distance of a line L from the origin l = 5 and let this perpendicular make an angle @ = pi/6 with the x axis. Determine the normal equation of l?
Plz show me working

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asked by sam
  1. pi/6 = 30 degrees
    our lines go though a point 5 units along there from origin
    x = 5 cos 30
    y = 5 sin 30
    that 30 degree line has slope sin30/cos30 = .577
    the perpendicular has slope
    -1/.577 = - 1.732
    so line is of form
    y = -1.732 x + b
    now put in y = 5 sin 30 and x = 5 sin 30 to get b

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    posted by Damon

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