Calculate the concentration of the initial nitrate stock solution (in ppm) if exactly 0.361 g of
KNO3 is dissolved in a 1 L volumetric flask with distilled water.
Here I want the concentration of nitrogen in ppm.
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To calculate the concentration of the initial nitrate stock solution in ppm (parts per million), you need to know the moles of KNO3 dissolved in the solution and the volume of the solution.
First, we need to calculate the moles of KNO3 using its molar mass. The molar mass of KNO3 is:
Molar mass of K = 39.10 g/mol
Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of KNO3 = (39.10 g/mol) + (14.01 g/mol) + (3 * 16.00 g/mol)
= 101.10 g/mol
Next, we can calculate the number of moles of KNO3 using the given mass:
Number of moles = Mass / Molar mass
= 0.361 g / 101.10 g/mol
≈ 0.003572 mol
Now, we need to convert the volume of the solution to liters. Since the solution is dissolved in a 1 L volumetric flask, the volume is simply 1 L.
Finally, we can calculate the concentration in ppm:
Concentration (in ppm) = (Number of moles / Volume in liters) * 10^6
= (0.003572 mol / 1 L) * 10^6
= 3572 ppm
Therefore, the concentration of the initial nitrate stock solution is approximately 3572 ppm of nitrogen.
You will have 1000.361 grams solution.
You have .361 grams solute
PPM=.361*10^6/1000.361=361000/1000.361= about 361ppm