Find the distance d(p1,p2) between the ponts p1 and p2.
P1=(-4,3); P2= (6,0)
d(P1,P2)= _____ Type an exact answer, using radicals as needed.
Pythagorean's theorem can be used from what I see. If you plot the points, you have P1 at (-4,3) and P2 (6,0). Draw a line giving a right angle at the (-4,0). Use the formula for the Pythagorean theorem: a^2+b^2=c^2; where side a is at -4, and side b is on the x axis. Solve for c, which will be your distance or d (P1,P2.)
Let me know if you get stuck.
I may have confused you with saying that side "a" is at a point. It is actually on the -4, from the x axis up to P1 and is 3 units long. Where side "b" is on the x axis and is 6 units in the right direction toward P2, plus 4 units toward the left, under P1, for a total of 10 units.
Using the formula: a^2+b^2=c^2
10^2+6^2=c^2
100+36=c^2
√136 = c
11.662 = c
To find the distance between two points, you can use the distance formula in coordinate geometry. The distance formula is given as:
d(p1,p2) = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Let's substitute the given coordinates into the formula:
P1 = (-4,3) --> x1 = -4 and y1 = 3
P2 = (6,0) --> x2 = 6 and y2 = 0
Now, we can calculate the distance:
d(P1, P2) = sqrt((6 - (-4))^2 + (0 - 3)^2)
Simplifying further:
= sqrt((6 + 4)^2 + (-3)^2)
= sqrt(10^2 + 9)
= sqrt(100 + 9)
= sqrt(109)
Therefore, the distance between the points P1 and P2 is sqrt(109).