A dolphin has 5,200,000 ppm of DDT. Phytoplankton contains 10 ppm. How many times greater is the concentration of DDT in the dolphin. My answer was 520,000 times greater Is my answer correct?
Also a
Sorry, I submitted the question before finishing it by accident. The next question was a squid contains 22,000 ppm of DDT. How much DDT would you consume if you ate 3kg of squid. My answer was 66,000 ppm. Is this answer correct? Thank you.
To determine if your answer is correct, you can calculate the concentration ratio between the dolphin and the phytoplankton. Let's divide the concentration of DDT in the dolphin by the concentration in phytoplankton:
Dolphin concentration = 5,200,000 ppm
Phytoplankton concentration = 10 ppm
Concentration ratio = Dolphin concentration / Phytoplankton concentration
= 5,200,000 ppm / 10 ppm
To simplify the calculation, we can cancel out the "ppm" units by dividing both numerator and denominator by 10.
Concentration ratio = 520,000 ppm
Thus, the concentration of DDT in the dolphin is 520,000 times greater than the concentration in phytoplankton.
Hence, your answer of 520,000 times greater is correct.