Type in the two equations you used to solve the problem below and then state the values of x.

2x - 4 = 22

x = ?

2x - 4 = -22

x = ?

Can someone walk me through on how to find the values of x?

Oops, forgot to write the initial equation: |2x - 4| = 22

2x - 4 = 22 and 2x - 4 = -22

I assume you know how to solve these

I don't know how to solve those, that's why I asked if someone can walk me through the process of solving them.

2x-4 = 22

2x = 26
x = 13

same way for the other

To find the values of x in the given equations, we can use a method called algebraic manipulation. Let's solve the equations step by step.

Equation 1: 2x - 4 = 22
To isolate the variable x, we need to get rid of the constant term (-4) on the left side of the equation. We can do this by performing inverse operations.

Adding 4 to both sides of the equation:
2x - 4 + 4 = 22 + 4
2x = 26

Now, we want to isolate x. Since x is multiplied by 2, we can divide both sides of the equation by 2:
(2x)/2 = 26/2
x = 13

So, the solution to Equation 1 is x = 13.

Equation 2: 2x - 4 = -22
Similar to the previous equation, we will perform inverse operations to isolate the variable x.

Adding 4 to both sides of the equation:
2x - 4 + 4 = -22 + 4
2x = -18

Dividing both sides of the equation by 2:
(2x)/2 = -18/2
x = -9

Therefore, the solution to Equation 2 is x = -9.

In conclusion, the values of x for the given equations are x = 13 and x = -9.