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find the equation of the hyperbola with vertices (4,0), (-4,0) and focus (7,0)
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What do you know about the values of
a, b, and c in a hyperbola?
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A hyperbola has vertices (4,0) and one focus (5,0). What is the standard-form equation of the hyperbola?
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Since the vertices are on the x-axis, we know that this is a horizontal hyperbola. The distance from
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Can someone please help...
a hyperbola has vertices (+-5,0) and one focus (6,0) what is the standard form equation of the
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The equation for this porblem is (x-25)-(y/11)=1
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a hyperbola has vertices (+-5,0) and one focus (6,0) what is the standard form equation of the hyperbola.
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The standard form equation of the hyperbola: x² / a² - y² / b² = 1 a = 5, a² = 25 c = 6 c² =
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Find the equation of the hyperbola whose vertices are at (-1,-5) and
(-1,1) with a focus at (-1,-7). Please and thank you.
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centre must be the midpoint of the vertices centre is (-1, -2) after making a sketch we can see the
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Find the equation of the hyperbola whose vertices are at (-1,-5) and
(-1,1) with a focus at (-1,-7). Please and thank you.
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Since the vertices and focus are on the same vertical line (x = -1), this hyperbola has an equation
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Find the equation of the hyperbola whose vertices are at (-1,-5) and (-1,1) with a focus at (-1,-7).
So far I have the center at
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Hmmm. I don't know what you mean by c. (y+2)<sup>2</sup>/a<sup>2</sup>
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A hyperbola centered at (0, 0) has vertices (15, 0) and (-15, 0) and one focus at (17, 0). What is the standard-form equation of
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The standard form equation for a hyperbola centered at the origin is: $\frac{x^2}{a^2} -
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a hyperbola of eccentricity 3/2 has one focus at (1,-3). The corresponding directrix is the line "y". find an equation for the
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To find the equation of the hyperbola, we need to determine the center, the vertices, and the
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.Find the standard equation of the hyperbola whose conjugate axis is on the directrix of the parabola 𝑦^2 + 12𝑥 + 6𝑦 =
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y^2 + 6y + .... + 12x = 39 y^2 + 6y + 9 + 12x = 39+9 (y+3)^2 - 48 = -12x x = -(1/12)(y+3)^2 + 4 so
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Find an equation for the hyperbola described:
1) Vertices at (0,+/- 10); asymptotes at y= 5/3x 2) Vertices at (-+5,0); foci at
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1) To find the equation for the hyperbola with vertices at (0, ±10) and asymptotes at y = (5/3)x,
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