How do I solve this
(3x^4y)^3
3^3 = 27
(x^4)^3 = x^12
so
27 x^12 y^3
Thanks
You are welcome.
To solve the expression (3x^4y)^3, we need to apply the exponent rule of raising a power to another power. Here's how you can do it step by step:
Step 1: Distribute the exponent 3 to both the base 3x^4y.
(3x^4y)^3 = 3^3 * (x^4)^3 * y^3
Step 2: Simplify the exponent of the base 3.
3^3 = 27
(27) * (x^4)^3 * y^3
Step 3: Simplify the exponent of the base x^4.
(x^4)^3 = x^(4*3) = x^12
27 * x^12 * y^3
Step 4: Simplify the expression further.
The final answer is 27x^12y^3.
So, (3x^4y)^3 simplifies to 27x^12y^3.