An open box, no more than 5 cm in height, is to be formed by cutting four identical squares from the corners of a sheet of metal 25 cm by 32 cm, and folding up the metal to form sides. The capacity of the box must be 1575 cm^3. What is the side length of the squares removed?
im getting the length of the square to be 9.1 but it says im wrong..
http://www.jiskha.com/display.cgi?id=1469498774
Thanks!
You're welcome.
To find the side length of the squares that are removed, we can use the formula for the volume of a box:
Volume = Length * Width * Height
In this case, the length of the box is 32 cm, the width is 25 cm, and the height is the side length of the squares that are being removed. We're given that the volume of the box must be 1575 cm^3.
So we can set up the equation:
32 * 25 * x = 1575
where x represents the side length of the squares to be removed.
Simplifying the equation, we get:
800x = 1575
Dividing both sides by 800, we find:
x = 1.96875
Rounding to the nearest tenth, we get:
x ≈ 1.97 cm
Therefore, the side length of the squares to be removed should be approximately 1.97 cm.