kashinath palod

an object of mass 3 kg is at rest. Now a force of vectorS = 6t2^i + 4tj^ is applied on the object then velocity of object at t = 3 sec. is?

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  1. FF = ma = 6t^2i + 4tj
    Since m=3,
    a = 2t^2i + 4/3 t j
    so,
    v = 2/3 t^2 i + 2/3 t^2 j

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  2. Oops --
    v = 2/3 t^3 i + 2/3 t^2 j

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  3. Dun public school

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