An object is dropped from a bridge. Find the distance the object has fallen when its speed reaches 132 ft/s. Use the equation
v =
64d
,
where v is the speed in feet per second and d is the distance in feet.
the drop time is
... t = 132 ft/s / 32 ft/s²
it starts from rest, so the average velocity is ... (0 + 132) / 2 ft/s
the distance is
... d = drop time * average velocity
To find the distance the object has fallen when its speed reaches 132 ft/s, we can use the equation:
v = 64d
We are given that v = 132 ft/s, so we can substitute this value into the equation:
132 = 64d
Now, let's solve for d by isolating the variable:
Dividing both sides of the equation by 64:
132/64 = d
Simplifying the right side:
d ≈ 2.06
Therefore, the distance the object has fallen when its speed reaches 132 ft/s is approximately 2.06 feet.
To find the distance the object has fallen when its speed reaches 132 ft/s, we can use the given equation v = 64d.
We are given that the speed is 132 ft/s, so we can plug this value into the equation:
132 = 64d
To solve for d, we need to isolate it on one side of the equation.
Dividing both sides of the equation by 64, we get:
d = 132/64
Using a calculator, we can find that d is approximately 2.06 feet.
Therefore, the distance the object has fallen when its speed reaches 132 ft/s is approximately 2.06 feet.