How many joules are required to convert 34 grams of ice at 0 degrees celcius to water at the same temperature?
(Can you please show how you go the answer)Thanks!
Heat required to melt ice=Hf*mass
Look up the Heat of fusion of ice.
Note the correct spelling of Celsius.
To calculate the number of joules required to convert 34 grams of ice at 0 degrees Celsius to water at the same temperature, you need to consider two steps:
1. First, you need to determine the amount of energy required to change the ice from its solid state to its liquid state. This process is called the heat of fusion.
The heat of fusion for water is 334.16 J/g. This means that it takes 334.16 joules of energy to convert 1 gram of ice into water at 0 degrees Celsius.
So, to calculate the energy required to convert 34 grams of ice to water, we can use the formula:
Energy = Mass × Heat of Fusion
Energy = 34 grams × 334.16 J/g
Energy = 11348.24 joules
Therefore, it would take approximately 11348.24 joules of energy to convert 34 grams of ice at 0 degrees Celsius to water at the same temperature.
2. The second step involves considering the energy required to raise the temperature of the ice/water from 0 degrees Celsius to a higher temperature. However, since the question specifies that the conversion is happening at the same temperature (0 degrees Celsius), we can ignore this step and focus only on the heat of fusion.
So, the final answer is 11348.24 joules.