For a population with a mean of 80 and the standard deviation of 12, what is the Z score corresponding to an individual score of 71?
you can play around with Z table stuff at
http://davidmlane.com/hyperstat/z_table.html
-.5
To find the Z score corresponding to an individual score of 71, you can use the formula for Z score:
Z = (X - μ) / σ
Where:
Z is the Z score
X is the individual score
μ is the mean of the population
σ is the standard deviation of the population
In this case:
X = 71
μ = 80
σ = 12
Substituting the given values into the formula:
Z = (71 - 80) / 12
Z = (-9) / 12
Z = -0.75
Therefore, the Z score corresponding to an individual score of 71 is -0.75.
No need to play, just insert data and solve.
Z = (score-mean)/SD