# Calculus

find the value of a, if it exists, such that the following function is continuous at X = 2.

piecewise function
f(x)={x^2-3x+1, if x>2; a, if x=2; 3-2x, if x<2

I found the limits from left and right of 2 = -1 so the limit exists but I don't know how to figure out a

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1. Am I missing something? If the limit from the left is -1, and the limit from the right is -1, and the function is continous, then the limit at the point is -1

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bobpursley
2. So a=-1 That makes sense because it's continuous

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3. to make it continuous f(2)=a so it would equal -1?

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