If 10g of magnesium reacted with 5g of oxygen how much magnesium oxide would you produce? How do you know?

To determine the amount of magnesium oxide that would be produced when 10g of magnesium reacts with 5g of oxygen, we need to employ stoichiometry and the concept of molar ratios.

First, we need to find the balanced chemical equation for the reaction between magnesium and oxygen. The balanced equation is:

2Mg + O2 -> 2MgO

According to this equation, 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.

Next, we need to convert the given masses of magnesium and oxygen into moles. To do this, we use the molar mass of each element.

The molar mass of magnesium (Mg) is 24.31 g/mol, so 10g of Mg is equivalent to 10/24.31 ≈ 0.411 moles of Mg.

The molar mass of oxygen (O2) is 32 g/mol, so 5g of O2 is equivalent to 5/32 ≈ 0.156 moles of O2.

Now, we can determine the limiting reactant. The reactant that is completely consumed, thus limiting the amount of product formed, is known as the limiting reactant. In this case, we compare the moles of Mg and O2. According to the reaction, it takes 2 moles of Mg for every 1 mole of O2. Since we have less than half the necessary moles of O2 compared to Mg, O2 is the limiting reactant.

Since O2 is the limiting reactant, it will determine the amount of product formed. From the balanced equation, we know that for every 1 mole of O2, we obtain 2 moles of MgO. Therefore, with 0.156 moles of O2, we will produce 2 * 0.156 = 0.312 moles of MgO.

Finally, we can convert the moles of MgO to grams using the molar mass of MgO. The molar mass of magnesium oxide (MgO) is 40.31 g/mol. Therefore, 0.312 moles of MgO is equivalent to 0.312 * 40.31 g ≈ 12.59 grams of MgO.

Thus, when 10g of magnesium reacts with 5g of oxygen, approximately 12.59 grams of magnesium oxide would be produced based on stoichiometry and molar ratios.

2Mg + O2 ==> 2MgO

mols Mg = grams/atomic mass = ?
Using the coefficients in the balanced equation, convert mols Mg to mols MgO. In this case that is mols Mg x 1 = mols MgO

Then convert mols MgO to grams.
g MgO = mols MgO x molar mass MgO = ?