show by calculation of z the behavior of (.25 mole) gas sample at the following conditions (ideal or real)at temperature 100c
1-p=0.25 v=12
To determine the behavior of the gas sample at the given conditions, we need to use the Ideal Gas Law equation, which is:
PV = nRT
where:
P represents the pressure of the gas,
V represents the volume of the gas,
n represents the amount of gas in moles,
R is the ideal gas constant (which is 0.0821 L·atm/mol·K for this calculation), and
T represents the temperature of the gas in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15.
So, T = 100 + 273.15 = 373.15 K
Now, we can rearrange the Ideal Gas Law equation to solve for the unknown variable, which in this case is the pressure (P):
P = (nRT) / V
Given that n = 0.25 moles, R = 0.0821 L·atm/mol·K, T = 373.15 K, and V = 12 L, we can substitute these values into the equation:
P = (0.25 * 0.0821 * 373.15) / 12
P = 0.638 atm
Therefore, the pressure of the gas sample under the given conditions is approximately 0.638 atm. Since we used the Ideal Gas Law equation for the calculation, the behavior of the gas sample is considered ideal.