Compute the approximate density of methane, CH4, at 20oC and 5.00 atm. The molecular weight of methane is 16.0.

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  1. assume one mole (16grams)

    so volume= 22.4(273+20)/273*1atm/5atm

    volume=4.81 liters

    denstiy=16/4.81 g/liter

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  2. dude thank you so much

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  3. From Ideal Gas Law PV=nRT=(mass/fwt)RT => (mass/Vol)=Density=P(fwt)/RT
    P = 5 Atm
    fwt = 16 g/mol
    R = 0.08206 L-Atm/mol-K
    T = (273+20)K = 293K
    Density = [(5)(16)/(0.08206)(293)]g/L
    = 3.33 g/L

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