Calculate the number of moles of solute in each of the following solutions:
Solution Moles of Solute
2.1 L of 0.21 M NH4HCO3
3.5 L of 0.28 M MgCO3
mols = M x L = ?
To calculate the number of moles of solute in a solution, you need to multiply the volume of the solution (in liters) by the molarity of the solute (in moles per liter). This gives you the number of moles of solute in the solution.
Let's apply this to the provided solutions:
1. Solution: 2.1 L of 0.21 M NH4HCO3
- Volume of solution: 2.1 L
- Molarity of NH4HCO3: 0.21 moles/L
- Number of moles of solute = Volume of solution x Molarity
- Number of moles = 2.1 L x 0.21 moles/L
- Number of moles = 0.441 moles
Therefore, there are 0.441 moles of NH4HCO3 in 2.1 L of a 0.21 M NH4HCO3 solution.
2. Solution: 3.5 L of 0.28 M MgCO3
- Volume of solution: 3.5 L
- Molarity of MgCO3: 0.28 moles/L
- Number of moles of solute = Volume of solution x Molarity
- Number of moles = 3.5 L x 0.28 moles/L
- Number of moles = 0.98 moles
Therefore, there are 0.98 moles of MgCO3 in 3.5 L of a 0.28 M MgCO3 solution.