8c) The scanning objective lens (4x) of a microscope has a diameter of field of 6.0 mm and a total magnification of 40x. The high power objective lens has a total magnification of 400x. Estimate the diameter of field of view of the high-power objective lens by using the following formula relating diameter of field to objective lens magnification for 2 objective lenses A and B:
diameter of field B = diameter of field A x (total magnification of lens A / total magnification of lens B)
0.1 mm
0.6 mm
60 mm
100 mm
HELP???
Well I got that one wrong for sure not 60mm
To estimate the diameter of the field of view of the high-power objective lens, you can use the provided formula:
diameter of field B = diameter of field A x (total magnification of lens A / total magnification of lens B)
In this case, the scanning objective lens (A) has a diameter of field of 6.0 mm and a total magnification of 40x. The high-power objective lens (B) has a total magnification of 400x.
By substituting the values into the formula, you get:
diameter of field B = 6.0 mm x (40x / 400x)
The 40x and 400x in the formula cancel out, leaving:
diameter of field B = 6.0 mm / 10
Simplifying further:
diameter of field B = 0.6 mm
Therefore, the estimated diameter of the field of view of the high-power objective lens is 0.6 mm.