During the month of June, Ava kept track of the number of days she saw birds in her garden. She saw birds on 18 days of the month. What experimental probability that she will see birds in her garden on July 1?
Can somebody show me how to work this problem out?
0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
To calculate the experimental probability, you need to divide the number of times an event occurred by the total number of trials or opportunities for the event to occur.
In this case, Ava saw birds in her garden on 18 days out of the total month of June, which usually has 30 days.
So, the experimental probability of Ava seeing birds in her garden on any given day can be calculated by dividing the number of days she saw birds (18) by the total number of days in June (30).
Experimental probability = Number of successful outcomes / Total number of trials
Experimental probability = 18 / 30
Now, you can simplify this fraction if needed. In this case, both 18 and 30 are divisible by 6, so you can divide both by 6 to simplify the fraction:
Experimental probability = 3 / 5
Therefore, the experimental probability that Ava will see birds in her garden on July 1 is 3/5 or 0.6.
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6
probability that she sees a bird on any old day = 18/30 = 0.6