how do i solve log(8y-7)/logy
depends on what you mean by "solve"
It is log7(8y-7)
sorry. I meant
logy(8y-7)
To solve the expression log(8y-7)/logy, we need to simplify it using logarithm rules.
First, let's manipulate the expression by applying the quotient rule of logarithms, which states that log(a) - log(b) = log(a/b):
log(8y-7) / log(y) = log(8y-7) - log(y)
Now, let's simplify further by applying the logarithm property that states log a^n = n log a:
= log((8y-7)^1) - log(y^1)
= log(8y-7) - log(y)
Therefore, the solution to log(8y-7)/logy is log(8y-7) - log(y).