What mass of CaO, can get by the decomposition of 250 g of CaCo3 with 80% purity?
CaCO3 ==> CaO + CO2
grams CaCO3 = 250 x 0.8 = 200g.
mols CaCO3 = 200/molar mass CaCO3
Using the coefficients in the balanced equation, convert mols CaCO3 5o mols CaO.
Now convert mols CaO to g. g CaO = mols CaO x molar mass CaO.
To determine the mass of CaO that can be obtained from the decomposition of 250 g of CaCO3 with 80% purity, we can follow a step-by-step approach:
1. Calculate the amount of CaCO3 in the 250 g sample:
Mass of CaCO3 = 250 g × purity (80% or 0.8)
= 250 g × 0.8
= 200 g
2. Determine the molar mass of CaCO3:
The molar mass of CaCO3 is the sum of the atomic masses of Ca, C, and 3O.
Molar mass of Ca = 40.08 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (3 × 16.00 g/mol)
= 100.09 g/mol
3. Calculate the moles of CaCO3:
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
= 200 g / 100.09 g/mol
= 1.999 mol (approximately 2 mol)
4. The molar ratio of CaCO3 to CaO is 1:1 because one mole of CaCO3 decomposes to produce one mole of CaO.
5. Calculate the moles of CaO:
Moles of CaO = Moles of CaCO3
= 2 mol
6. Determine the molar mass of CaO:
The molar mass of CaO is the atomic mass of Ca plus the atomic mass of O.
Molar mass of Ca = 40.08 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of CaO = 40.08 g/mol + 16.00 g/mol
= 56.08 g/mol
7. Calculate the mass of CaO:
Mass of CaO = Moles of CaO × Molar mass of CaO
= 2 mol × 56.08 g/mol
= 112.16 g
Therefore, by decomposing 250 g of CaCO3 with 80% purity, approximately 112.16 g of CaO can be obtained.