Spring of 20cm extend to 30cm under a force of 10N.what will be its total length when extended by a force of 10N?
Umm. Didn't you just tell me 30cm
To find the total length of the spring when extended by a force of 10N, we need to understand Hooke's Law, which states that the extension of a spring is proportional to the force applied to it.
Hooke's Law can be represented by the equation:
F = kx
where:
F is the force applied to the spring,
k is the spring constant,
x is the extension of the spring.
To find the spring constant (k), we can rearrange the equation to solve for k:
k = F / x
Given that the spring extends from 20cm to 30cm under a force of 10N, the extension (x) is calculated as:
x = 30cm - 20cm = 10cm
Now we can find the value of the spring constant (k):
k = 10N / 10cm = 1 N/cm
To determine the total length of the spring when extended by a force of 10N, we can use the following equation:
F = kx
Substituting the given force and the calculated spring constant:
10N = (1 N/cm) * x
Solving for x:
x = 10N / (1 N/cm) = 10 cm
Therefore, the total length of the spring when extended by a force of 10N is 30cm (initial length) + 10cm (extension) = 40cm.