Hello, could someone help me set up the equation for this word problem?
A sharpshooter intends to hit a target at a distance of 3000ft with a gun that has a muzzle velocity of 1200 ft per second. Neglecting air resistance, determine the gun's minimum angle of elevation theta if the range r is given by r=1/32v^2/0sin(2theta). Round your angle to nearest tenth of a degree.
Range = (1200)^2*sin(2A)/32 = 3000,
45,000*sin(2A) = 3000,
sin(2A) = 0.0667,
2A = 3.82,
A = 1.9 Degrees.