physics

A 56.0-kg skater is traveling due east at a speed of 2.80 m/s. A 77.0-kg skater is moving due south at a speed of 4.40 m/s. They collide and hold on to each other after the collision, managing to move off at an angle south of east, with a speed of vf. Find (a) the angle and (b) the speed vf, assuming that friction can be ignored.

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asked by chris
  1. The momentum is conserved. Therefore the final momentum has E and S as before.

    Momentum E=56*2.8
    momentum S=4.4*77

    Use these to get the angle

    arctanTheta=MomentumS/momentumE
    where theta is the angle S of E.

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