Points J and K, plotted on the coordinate grid, are two vertices of rectangle JKLM.
Rectangle JKLM has an area of 7 square units.
Point J is located at (2, 1) and point K is located at (-5, 1).
Each vertex of the rectangle is located at a point that has integer coordinates.
clearly the width is 7, since JK is a horizontal line.
so the height is 1.
To find the other two vertices of the rectangle JKLM, we need to consider its area and the coordinates of J and K.
First, let's find the length of the base of the rectangle. The base of the rectangle is the distance between J and K, which can be found using the formula for distance between two points:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Using the coordinates of J (2, 1) and K (-5, 1), we can calculate the distance between them:
Distance = sqrt((-5 - 2)^2 + (1 - 1)^2)
= sqrt((-7)^2 + 0^2)
= sqrt(49)
= 7
So, the length of the base of the rectangle JKLM is 7 units.
Next, we can use the area of the rectangle to find its height. The area of the rectangle is given as 7 square units. Since the base of the rectangle is 7 units, we can solve for the height using the formula for the area of a rectangle:
Area = base * height
7 = 7 * height
height = 1
Therefore, the height of the rectangle JKLM is 1 unit.
Now, we can find the other two vertices of the rectangle.
Since point J is located at (2, 1), we can move 1 unit up (since the height is 1) to find vertex M:
Vertex M = (2, 1 + 1) = (2, 2)
Similarly, since point K is located at (-5, 1), we can move 1 unit up to find vertex L:
Vertex L = (-5, 1 + 1) = (-5, 2)
So, the other two vertices of the rectangle JKLM are M(2, 2) and L(-5, 2).