In the lab, you mix 30mL of 0.30M Na2SO4 with 10mL of 0.25M Ba(OH)2 to produce BaSO4 and NaOH. Calculate the theoretical yield (in moles) of BaSO4 produced from this reaction. State your answer in decimal form and round to two sig. fig. (not scientific notation).

Na2SO4+Ba(OH)2>>BaSO4+2NaOH

moles Na2SO4=.03*.3=.009moles
moles Ba(OH)2=.01*.25=.0025moles

but the reaction is restriced to the least moles of the reactant, so Ba(OH)2 is the determinant, so we get .0025 moles BaSO4

Check my thinking and math.