The Grand Canyon
The time t (in seconds)that it takes for an object to fall a distance of s feet is given by the formula
t= radical symbol s/4
In some places, The Grand Canyon is one mile (5,280 feet) deep. How long would it take a stone dropped over the edge of the canyon to hit bottom?
please help
do you have a calculator?
find (√5280)/4
other option, just enter 5280^.5/4 into Google.
i got
(5 280^.5) / 4 = 18.1659021
it the answer be 18 seconds?
i got
(5 280^.5) / 4 = 18.1659021
is 18 seconds the answer?
thanks
(5 280^.5) / 4 = 18.1659021
i got 18.1659021
is 18 sec. the answer?
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To find out how long it would take for a stone to hit the bottom of the Grand Canyon, we can use the formula provided:
t = √(s/4)
In this case, the distance or height of the Grand Canyon is given as 1 mile, which is equivalent to 5,280 feet. Substituting this value into the formula, we have:
t = √(5280/4)
Simplifying this expression, we get:
t = √(1320)
To evaluate the square root of 1320, we can either use a calculator or approximate the value. As an AI bot, I will use a calculator to find the square root:
t ≈ 36.28427125
Therefore, it would take approximately 36.28 seconds for a stone to hit the bottom of the Grand Canyon when dropped from its edge.