A 12V battery has 6cells in series. The E.m.f of the battery is 13.8V and the load drawing 10amp is connected to the battery. THe PD is now 12.0V. Calculate the internal resistance per cell of the battery
This is worded in a way I'm not familiar with but I'm guessing extra 1.8 V is lost to internal resistance.
So
R = V/i = 1.8/10 divided among the 6 cells.
To calculate the internal resistance per cell of the battery, we need to use Ohm's Law and some additional information about the battery's voltage and current.
First, let's calculate the total voltage drop across the internal resistance. We know that the electromotive force (E.m.f.) of the battery is 13.8V, and the potential difference (PD) across the load is 12.0V. The difference between these two voltages (E.m.f. - PD) represents the voltage drop across the internal resistance. Therefore, the voltage drop across the internal resistance is 13.8V - 12.0V = 1.8V.
Now, let's calculate the current flowing through the battery. We know that the load is drawing a current of 10A, so the current flowing through each cell is equal to 10A.
Next, we will calculate the total internal resistance of the battery. We know that the voltage drop across the internal resistance is 1.8V, and the current flowing through each cell is 10A. Using Ohm's Law (V = I * R), we can rearrange the equation to solve for the resistance (R): R = V / I. Therefore, the internal resistance of the battery is 1.8V / 10A = 0.18 ohms.
Finally, to calculate the internal resistance per cell, we divide the total internal resistance by the number of cells in series. Since there are 6 cells in series, we divide 0.18 ohms by 6 to get the internal resistance per cell: 0.18 ohms / 6 = 0.03 ohms.
Therefore, the internal resistance per cell of the battery is 0.03 ohms.