# Physics

The moon has a period of 27.3 days and a mean distance of 3.90 x 10^5 km from the center of Earth.

a) Use Kepler's laws to find the period of a satellite in orbit 6.70 x 10^3 km from the center of Earth
--- I was able to do this and the answer i got was: 88.6 mins, but was stuck on the 2nd part of this question, which is below:

b)How far above Earth's surface is this satellite?

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1. You have the mean distance from the center of Earth. Normally, one might subtract the thickness of the Earth from the center to get the distance from the Surface .

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2. you have to subtract the radius of earth from the total radius

so:
6.7x10^3-6.38x10^3

=0.4 km
or
=400 m

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posted by Captain

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