An object 20cm high is placed 40cm from a lens of focal length 24cm. Calculate:
a) The power of the Lens?
b) The distance from the lens to the position of the image?
b) 1/p + 1/q = 1/f so
1/40 + 1/q = 1/24
a)I assume they mean magnification M = -q/p
The gradient of a curve is defined by
dy/dx = 3x^(1/2) - 6
Given the point (9, 2) lies on the curve, find the equation of the curve
To calculate the power of the lens, you can use the formula:
Power (P) = 1 / focal length (f)
a) The focal length of the lens is given as 24 cm, so you can substitute the value into the formula:
P = 1 / 24 cm = 0.0417 diopters
Therefore, the power of the lens is 0.0417 diopters.
To calculate the distance from the lens to the position of the image, you can use the lens formula:
1 / object distance (u) + 1 / image distance (v) = 1 / focal length (f)
b) The object distance (u) is given as 40 cm, and we need to find the image distance (v). Substitute these values into the lens formula:
1 / 40 cm + 1 / v = 1 / 24 cm
To solve for v, cross multiply and simplify:
1 / v = (1 / 24 cm) - (1 / 40 cm)
1 / v = (40 - 24) / (24 * 40) cm
1 / v = 16 / (24 * 40) cm
Now, take the reciprocal of both sides to find the value of v:
v = (24 * 40) / 16 cm
Calculate further:
v = 960 / 16 cm
v = 60 cm
Therefore, the distance from the lens to the position of the image is 60 cm.