Sam is 9 years older than angel. Six years from now, Sam age will be thrice the age of angel 3 years ago. Find their present ages.
Please help me with this. ASAP. Thanks
Let x be Sam's age and y be Angel's age.
"Sam is 9 years older than Angel."
x = y + 9
"Six years from now..."
x + 6
"...thrice the age of Angel 3 years ago".
3(y - 3)
x + 6 = 3(y - 3)
To solve this problem, we need to set up equations based on the given information and solve them simultaneously.
Let's assign variables to represent Sam's and Angel's ages:
Let S = Sam's present age
Let A = Angel's present age
Based on the problem, "Sam is 9 years older than Angel," we can write the equation: S = A + 9
The problem also states that "Six years from now, Sam's age will be thrice the age of Angel 3 years ago." This gives us another equation:
(S + 6) = 3(A - 3)
Now we have a system of two equations:
S = A + 9
S + 6 = 3(A - 3)
To solve the system, we can use substitution or elimination method. Let's use substitution:
Substitute the value of S from the first equation into the second equation:
(A + 9) + 6 = 3(A - 3)
Simplify:
A + 15 = 3A - 9
Isolate the variable:
15 + 9 = 3A - A
24 = 2A
Divide both sides by 2:
A = 12
Now that we know Angel's present age is 12, we can substitute this value back into the first equation to find Sam's present age:
S = A + 9
S = 12 + 9
S = 21
Therefore, Sam's present age is 21 and Angel's present age is 12.
In summary, Sam's present age is 21 and Angel's present age is 12.