A body is displaced through a certain distance x by a force of 30 newtons.if the work done is 100 joules and the displacement is in the direction of force,what is the value of x?
W=F×X
100=30×X
30X=100
100\30
X=3.3
Work done=f*d
100=30*x
100/30=x
x=3.3m
Work done = 100 joules
Work = force distance
100 joules = 30 newton
X= 100/30meter
X= 3.3meter
Work =f*x
100=30*x
30x=100
X=100/30
=3.3
work=force*distance
100joules=30N*x
x=100/30 meters
Work=force*distance=100=30*x=100/30=3.3
Work done= 100J
W=F×distance
100J=30newto
X= 100/30 meter
X=3.3 meter
X=3.3
Let the s be x
Given
W=100j
F=30N
D=?
Given
W=f*s
100=30*x
100/30=x
X=3.3
Work done =100j
W=f* distance
100j= 30newton
X=100/30
=3.3
W=F*X
100=30*X
30X=100
100/30
X=3.3
W=f×x
100=30×x
100=30x
100/30
X=3.3
Miracle
Work=force ×X
100w=30f×X
X=100/30
X=3.3
A body is displaced at a certain distance x by a force of 30N. If the work done is 100J, what is the value of x?
Correct! The distance the body is displaced is 3.3 meters.
W=F*x
100=30*x
30x=100
100/30
=3.3//
100=30×x
100=30x
100/30=3.3
X=3.3
Work done= force × distance
100= 30 × x
100=30x
100\30=x
X=3.3
F=30
W=100
Formula
Work=force ×distance
100=30×x
100=30x
Divide by co efficient of x
100/30
=3.3