how many electrons are in the sodium sulphate?
in a molecule of Na2SO4 ? count the atomic number of sodium, times two, add the atomic number of Sulfur, then add the atomic number of oxygen times 4.
That is the number of protons, and the number of electrons.
You asked a very odd question, I am uncertain if you intended asking something else.
To determine the number of electrons in sodium sulfate (Na2SO4), we need to consider the number of electrons in each atom present in the compound.
Sodium (Na) has 11 electrons per atom, and there are 2 sodium atoms in sodium sulfate, so 2 x 11 = 22 electrons from sodium.
Sulfur (S) has 16 electrons per atom, and there is 1 sulfur atom in sodium sulfate, so 1 x 16 = 16 electrons from sulfur.
Oxygen (O) has 8 electrons per atom, and there are 4 oxygen atoms in sodium sulfate, so 4 x 8 = 32 electrons from oxygen.
Summing up all the electrons, we have 22 + 16 + 32 = 70 electrons in sodium sulfate.
To determine the number of electrons in sodium sulfate (Na2SO4), you need to know the electronic configurations of the atoms involved.
First, let's look at the electronic configuration of sodium (Na). Sodium has an atomic number of 11, which means it has 11 electrons. The electronic configuration of sodium is 1s2 2s2 2p6 3s1, indicating that it has one valence electron in the 3s orbital.
Next, let's consider the sulfate ion (SO4^2-). To determine the number of electrons in the sulfate ion, we need to add up the total number of valence electrons of each atom involved.
The sulfur (S) atom has an atomic number of 16 and an electronic configuration of 1s2 2s2 2p6 3s2 3p4. In the sulfate ion, there are four oxygen (O) atoms, each with an atomic number of 8 and an electronic configuration of 1s2 2s2 2p4.
So, the total number of valence electrons in the sulfate ion is calculated as follows:
Sulfur (S): 6 valence electrons (4 from the 3s orbital and 2 from the 3p orbital)
Oxygen (O): 4 valence electrons (2 from the 2s orbital and 2 from the 2p orbital)
Thus, the total number of valence electrons in the sulfate ion is 6 + (4 x 4) = 22 valence electrons.
In sodium sulfate (Na2SO4), there are two sodium atoms, each contributing one valence electron, and one sulfate ion, contributing a total of 22 valence electrons. Therefore, the total number of electrons in sodium sulfate is 2 + 22 = 24 electrons.