Divide 59ml into two parts such that one part is 7ml less than 5times the second one
x + (5x-7) = 59
6x = 66
x = 11
and
5x - 7 = 55-7 = 48
To divide 59ml into two parts, let's assume the first part is represented by x ml and the second part is represented by y ml.
According to the given conditions, we have the equation:
x = 5y - 7
Now we can solve this equation to find the values of x and y.
Step 1: Substitute the value of x from the equation into the other equation:
59 = x + y
Step 2: Substitute the value of x in terms of y from the first equation into the second equation:
59 = (5y - 7) + y
Step 3: Simplify the equation:
59 = 6y - 7
Step 4: Add 7 to both sides of the equation:
66 = 6y
Step 5: Divide both sides by 6:
y = 11
Step 6: Substitute the value of y back into the first equation to find x:
x = 5(11) - 7
x = 55 - 7
x = 48
Thus, the two parts are 48ml and 11ml.
14 - 45
Division
Thank u so much for the answer
P+Q=59
P=5Q-7
11ml, 48ml