Find two consecutive even numbers whose sum is 1306.
n + n+2 = 1306
2 n = 1304
n = 652
n+2 = 654
To find two consecutive even numbers whose sum is 1306, we can set up an algebraic equation.
Let's assume the first even number be "x". Since the numbers are consecutive even numbers, the second even number will be "x+2" because adding 2 to an even number gives the next consecutive even number.
Therefore, we can say that the sum of these two even numbers is given by the equation:
x + (x+2) = 1306
Simplifying the equation:
2x + 2 = 1306
Now, subtract 2 from both sides of the equation:
2x = 1306 - 2
2x = 1304
Divide both sides of the equation by 2 to solve for x:
x = 1304 / 2
x = 652
So, the first even number is 652. To find the second even number, we can substitute this value back into the equation:
x+2 = 652 + 2
x+2 = 654
Therefore, the two consecutive even numbers whose sum is 1306 are 652 and 654.