A customer at the ring toss booth gets eight rings for two dollars find the constant of proportionality and write an equation relating the cost to the number of rings. At the same rate how much would a customer pay for 11 rings? for 20 rings?
2d = 8r
d = 4r
now you can play around
To find the constant of proportionality, we need to determine the cost of one ring. The cost of 8 rings is given as $2.
To find the cost of one ring, we can divide the total cost by the number of rings: $2 ÷ 8 = $0.25.
Therefore, the constant of proportionality is $0.25 (the cost per ring).
To write an equation relating the cost to the number of rings, we can use the following formula:
Cost = Constant of Proportionality × Number of Rings
Since the constant of proportionality is $0.25, the equation becomes:
Cost = $0.25 × Number of Rings
To find the cost for 11 rings, we can substitute 11 for the number of rings in the equation:
Cost = $0.25 × 11 = $2.75
Therefore, a customer would pay $2.75 for 11 rings.
Similarly, to find the cost for 20 rings, we can substitute 20 for the number of rings:
Cost = $0.25 × 20 = $5
Therefore, a customer would pay $5 for 20 rings.